c^2-9c+2=0

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Solution for c^2-9c+2=0 equation: 



c^2-9c+2=0

a = 1; b = -9; c = +2;
Δ = b2-4ac
Δ = -92-4·1·2
Δ = 73
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-9)-\sqrt{73}}{2*1}=\frac{9-\sqrt{73}}{2}
$


$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-9)+\sqrt{73}}{2*1}=\frac{9+\sqrt{73}}{2}
$

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